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Q.

The standard Gibbs energy for the given cell reaction in kJmol1 at 298K is: 
Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s)
E=2V at 298K
(Faraday's constant, F = 96000 C mol-l)

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a

384

b

192

c

-384

d

-192

answer is A.

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Detailed Solution

ΔG=nFEcell 
=2×(96000)×2V=384000J/mol
= -384 kJ/mol

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The standard Gibbs energy for the given cell reaction in kJmol−1 at 298K is: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)E∘=2V at 298K(Faraday's constant, F = 96000 C mol-l)