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Q.

The standard Gibbs energy for the given cell reaction in KJ mol-1 at 298K is Zn(s)+Cu(aq)2+Zn(aq)2++Cu(s),  E°=2V at 298 K  (F = 96,000C)  
 

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a

384

b

192

c

-384

d

-192

answer is C.

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Detailed Solution

ΔG°=nECell°ΔG°=2×96000×21000KJ ΔG°=3840001000KJ ΔG°=384KJ

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The standard Gibbs energy for the given cell reaction in KJ mol-1 at 298K is Zn(s)+Cu(aq)2+→Zn(aq)2++Cu(s),  E°=2V at 298 K  (F = 96,000C)