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Q.

The standard molar enthalpies of formaton of IF3 (g) and IF5(g) are -470 kJ and -847 kJ, respectively. Valence shell electron-pair repulsion theory predicts that IF3(g)) is square pyramidal in shape in which all I-F bonds are equivalent while IF3 (g) is T-shaped (based on trigonal-bipyramidal geometry) in which I-F bonds are of different lengths. It is observed that the axial I-F bonds in IF3 are equivalent to the I-F bonds in IF5 • Calculate the equatorial  I-F bond strength (in kJ/mol) in IF 3 • Some other information's given are :

I2(s)I2(g); ΔH=62kJ

F2(g)2F(g); ΔH=155kJ

I2(g)2I(g); ΔH=149kJ

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answer is 272.

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Detailed Solution

847=31+1492+155×525ϵ1Fax

ϵ1F ax. =268

470=31+1492+155×322×268+ϵ1eq.

ϵ1F eq =272

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