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Q.

The standard reduction potential data at 25°C is given below:
E0Fe3+,Fe2+=+0.77V;E0Fe2+,Fe=0.44V;E0Cu2+,Cu=+0.34V;E0Cu+,Cu=+0.50VE0O2(g)+4H++4e2H2O=+1.23V;E0O2(g)+2H2O+4e4OH=+0.40VE0Cr3+,Cr=0.74V;E0Cr2+,Cr=0.91V;
Match E0 of the redox pair in Column-I with the values given in List-II and select the correct answer using the code given below the lists.
 

S.No.Column-IS.No.Column-II
A)E0Fe3+,Fep)–0.18V
B)E04H2O4H++4OHq)–0.4V
C)E0Cu2++Cu2Cu+r)–0.04V
D)E0Cr3+,Cr2+s)–0.83V

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a

A - p; B - q;C- r; D - s;

b

A - r; B -s ;C- q; D - p;

c

A-r; B-s; C-p; D-q

d

A - s; B - r;C- p; D - q;

answer is A.

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Detailed Solution

(A)r

3e+Fe3+Fe,3×E10e+Fe3+Fe2+,(1×0.77)2e+Fe2+Fe,(2×0.44)E10=0.04

(B)s

O2(g)+4H++4e2H2O;G1=-4F(1.23)O2(g)+2H2O+4e4OH;G2=-4F(0.40)4H2O4H++4OH-;G3=-4F(E3)G3=G1-G2=0.4-1.23=-0.83V

(C) p

Cu2++2e-Cu;G1=-2F(0.34);Cu++e-Cu ;G2=-F(+0.50)Cu+2+Cu2Cu+;G3=-FEG3=G1-G2=-0.68+0.5=-0.18 V

(D) q
Cr3++3eCr;G1=3F(0.74))Cr2++2eCr;G2=2F(0.91)Cr+3 + e Cr+2;G3=-FE3G3=G1-G2E3=0.4V;

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