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Q.

The standard reduction potential of a silver chloride electrode (metal-sparingly soluble salt electrode) is 0.209V and for silver electrodes 0.80V. If the moles of AgCl than can dissolve in 10L of 0.01M NaCl solution is represented as 10−x. Then x is 

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answer is 7.

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Detailed Solution

ECl−/AgCl/Ag0=EAg+/Ag0+0.05911logKSP      0.209=0.80+0.05911logKSP        KSP=10−10
Let solubility of AgCl in 0.01M solution is y then  10−10=y(y+0.01)⇒y=10−8
∴  moles of AgCl dissolved in 10L=10−8×10=10−7

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