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The standard reduction potentials for the two half-cell reactions are given below :
$large C{d^{2 + }}_{left( {aq} right)} + ,2{e^ - }, to ,C{d_{left( s right)}};,{E^0}, = , - 0.40V$

$large A{g^ + }_{left( {aq} right)} + ,{e^ - } to ,A{g_{left( s right)}};,{E^0}, = ,0.80V$

The standard free energy change for the reaction $large 2A{g^ + }_{left( {aq} right)}, + ,C{d_{left( s right)}}, to ,2A{g_{left( s right)}} + ,C{d^{2 + }}_{left( {aq} right)}$ is given by

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115.8 kJ

– 115.8 kJ

– 231.6 kJ

231.6 kJ

answer is C.

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Detailed Solution

ΔG^o = -nFE^o

= - 2 x 96500 x (0.8+0.4) = -231600 j = -231.6 kj

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