The states of hybridization of boron and oxygen atoms in boric acid $(H_{3} {BO}_{3})$ are respectively :

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$s p^{2}, s p^{3}$

$s p^{2}, s p^{2}$

$s p^{3}, s p^{3}$

$s p^{3}, s p^{2}$

answer is B.

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Detailed Solution

In boric acid, oxygen has 2 lone pairs and 2 bond pairs of electrons while B has 3 bond pairs of electrons. As a result, the hybridization of oxygen is ${sp}^{3}$ and that of boron is sp².

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