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The statue of liberty is made of $2.0 \times 10^{5}$ lbs of copper sheets bolted to a framework.
(1 lb = 454 g) ? (Atomic weight: Cu = 63.5). If number of atoms of copper on the statue present is $8.61 \times 10^{y}$ , find ‘y’ (Atomic mass of copper = 63.5)

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answer is 29.

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Detailed Solution

29
No of copper atoms $= \frac{2 \times 10^{5} \times 454}{63.5} \times 6.022 \times 10^{23}$
$= 8.61 \times 10^{29}$

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