The steam point and the ice point of a mercury thermometer are marked as $80^{0}$ and $20^{0}$ . What will be the temperature in centigrade mercury scale when this thermometer reads $32^{0}$

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$10^{0} C$

$30^{0} C$

$20^{0} C$

$0^{0} C$

answer is A.

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Detailed Solution

$r e l a t i o n b e t w e e n c e n t i g r a d e t h e r m o m e t e r a n d u n k n o w n t h e r m o m e t e r i s \frac{C}{100} = \frac{X - L F P}{U F P - L F P} C i s r e a d i n g o n c e n t i g r a d e t h e r m o m e t e r; X i s r e a d i n g o n u n k n w n t h e r m o m e t e r = 32 L F P i s l o w e r f i x e d p o i n t = 20; U F P i s u p p e r f i x e d p o i n t = 80 s u b s t i t u t e g i v e n v a l u e s i n a b o v e r e l a t i o n \Rightarrow \frac{C}{100} = \frac{32 - 20}{80 - 20} \Rightarrow \frac{C}{100} = \frac{12}{60} \Rightarrow C = \frac{120}{6} = 20^{0} C$