The steam point and the ice point of a mercury thermometer are wrongly marked as 92°C and 2°C respectively. The correct temperature read by this thermometer is

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2°C

5°C

10°C

20°C

answer is D.

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Detailed Solution

${(\frac{X - LFP}{UFP - LFP})}_{Faulty scale} = {(\frac{X - LFP}{UFP - LFP})}_{Celsius}$
But X = C = F
$(\frac{x - 2}{92 - 2}) = (\frac{x - 0}{100 - 0}); x = 20^{\circ} C$

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