The stoichiometry numbers of ${\mathrm{MnO}}_4^{-}, {\mathrm{Pb}}^{2+}$ and ${\mathrm{H}}_2\mathrm{O}$ in the balanced chemical equation of the reaction ${\mathrm{Mn}}^{2+}+{\mathrm{PbO}}_2+{\mathrm{H}}^{+}⟶{\mathrm{MnO}}_4^{-}+{\mathrm{Pb}}^{2+}+{\mathrm{H}}_2\mathrm{O}$, respectively, are

 

The correct balanced chemical equation is,

 $2{\mathrm{Mn}}^{2+}+5{\mathrm{PbO}}_2+4{\mathrm{H}}^{+}⟶2{\mathrm{MnO}}_4^{-}+5{\mathrm{Pb}}^{2+}+2{\mathrm{H}}_2\mathrm{O}$

From the above equation it is observed that the stoichiometry numbers of ${\mathrm{MnO}}_4^{-}, {\mathrm{Pb}}^{2+}$ and ${\mathrm{H}}_2\mathrm{O}$ in the balanced chemical equation of the reaction are 2, 5, 4.

Hence the correct option is A.