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The stop cock connecting two bulbs of volume 4 litre and 8 litre containing an areal gas at 7
atm and 6 atm respectively. Is opened. What is the final pressure in the two bulbs if the
temperature remains the same

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700.3 kPa

500.5 kPa

641.725 kPa

625.3 kPa

answer is A.

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Detailed Solution

$P = \frac{p_{1} v_{1} {+ p}_{2} v_{2}}{v_{1} {+ v}_{2}} = \frac{(4 5 7) + (8 × 6)}{4 + 8} = \frac{76}{12} = P = 6.33 atm$

$P = 6.33 × 10.1325 [1 atm = 101. 325 kpal]; P = 641.725 kpa$

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