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Q.

The stop cock connecting two bulbs of volume of 5 litre and 10 litre containing an ideal gas at 9 atm and 6 atm respectively, is opened. What is the final pressure in the two bulbs if the temperature remains the same

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answer is 7.

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Detailed Solution

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$\begin{array}{l} P_{1} V_{1} + P_{2} V_{2} = PR (V_{1} + V_{2}) \\ 9 \times 5 + 6 \times 10 = \underline{PR (5 + 10)} \\ 9 \times 5 + 6 \times 10 = \underline{PR (15)} \\ 45 + 60 = \underline{PR (15)} \\ PR = 7 atm \end{array}$

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