The stopping potential (V₀) versus frequency ( $\upsilon$ ) plot of a substance is shown in figure the threshold wave length is

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5x10¹⁴ m

6000Å

5000 Å

Can not be estimated from given data

answer is B.

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Detailed Solution

From the graph given we can write,
${\lambda _0} = \frac{c}{{{\nu _0}}} = \frac{{3 \times {{10}^8}}}{{5 \times {{10}^{14}}}} = 6 \times {10^{ - 7}}m = 6000\,{\AA}$

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