The straight line (1+2i)Z+(2i−1)Z¯=10i on the complex plane, has intercept on the imaginary axis is

(z−z¯)+2i(z+z¯)=10i⇒2iy+2i(2x)=10i⇒2x+y=5

(z−z¯)+2i(z+z¯)=10i⇒2iy+2i(2x)=10i⇒2x+y=5

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The straight line $(1 + 2 i) Z + (2 i - 1) \bar{Z} = 10 i$ on the complex plane, has intercept on the imaginary axis is

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$\frac{5}{2}$

$- \frac{5}{2}$

-5

answer is A.

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$\begin{array}{l} (z - \bar{z}) + 2 i (z + \bar{z}) = 10 i \\ \Rightarrow 2 iy + 2 i (2 x) = 10 i \\ \Rightarrow 2 x + y = 5 \end{array}$

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