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The straight wire AB carries a current I. The ends of the wire subtend angles $θ_{1} a n d θ_{2}$ at the point p as shown in figure. The magnetic field at the point p is ;

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$\frac{μ_{0} I}{4 π a} (\sin θ_{1} - \sin θ_{2})$

$\frac{μ_{0} I}{4 π a} (\sin θ_{1} + \sin θ_{2})$

$\frac{μ_{0} I}{4 π a} (\cos θ_{1} - \cos θ_{2})$

$\frac{μ_{0} I}{4 π a} (\cos θ_{1} + \cos θ_{2})$

answer is A.

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Detailed Solution

For a finite wire carrying a current the magnetic induction is given by equation

$\frac{μ_{0} i}{4 π d} (\sin θ_{1} + \sin θ_{2})$ in which we can substitute the values of $θ_{1} a n d θ_{2}$

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