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The straight wires $A B$ carries a current $I$ . The end of the wire subtend angles $θ_{1}$ and $θ_{2}$ at the point $P$ as shown in the figure. The magnetic field at the point $P$ is
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$\frac{μ_{0} I}{4 πa} (\sin θ_{1} - \sin θ_{2})$

$\frac{μ_{0} I}{4 πa} (\sin θ_{1} + \sin θ_{2})$

$\frac{μ_{0} I}{4 πa} (\cos θ_{1} - \cos θ_{2})$

$\frac{μ_{0} I}{4 πa} (\cos θ_{1} + \cos θ_{2})$

answer is A.

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Detailed Solution

The correct answer is $\frac{μ_{0} I}{4 πa} (\sin θ_{1} - \sin θ_{2})$ .

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