The strength of bonds formed by 2s-2s,2p-2p and 2p -2s overlap has the order :

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s-s > p-p> p-s

s-s > p-s> p-p

p-p > p-s > s-s

p-p > s-s > p-s

answer is C.

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Detailed Solution

When internuclear distance between two bonded atoms are nearly same then bond strength increase with increase in directional character.
Order of bond strength is (p-p)>(p-s)>(s-s).

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