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The stress versus strain graphs for wires of two materials A and B are as shown in the figure . If YA and YB are the Young’s modulii of the materials , then

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$Y_{B} = 2 Y_{A}$

$Y_{a} = Y_{b}$

$Y_{B} = 3 Y_{A}$

$Y_{A} = 3 Y_{B}$

answer is D.

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Detailed Solution

$\begin{array}{l} Y = \frac{S t r e e s}{S t r a i n} = T a n θ \\ \frac{Y A}{Y B} = \frac{T a n θ_{A}}{T a n θ_{B}} = \frac{T a n 60}{T a n 30} = 3 \\ Y_{A} = 3 Y_{B} \end{array}$

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