The structure of a basic amino acid, lysine, is given below
(A) The pKa₁, pKa₂ and pKa₃ of (A), respectively, are: 2.18, 8.95 and 10.53. What is the pH at isoelectric points(pI)?

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$\frac{{pKa}_{1} + {pKa}_{2}}{2}$

$\frac{{pKa}_{2} + {pKa}_{3}}{2}$

$\frac{{pKa}_{1} + {pKa}_{3}}{2}$

$\frac{{pKa}_{1} + {pKa}_{2} + {pKa}_{3}}{3}$

answer is C.

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Detailed Solution

$\frac{{pK}_{a_{2}} + {pK}_{a_{3}}}{2}$ If there are more than one amine group then we will take the average of pKa of amine groups, $pI = \frac{{pK}_{a_{2}} + {pK}_{a_{3}}}{2}$

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