Q.

The structure of ICl4 is

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a

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b

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c

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d

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answer is A.

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Detailed Solution

The structure of ICl₄⁻ (tetraiodide anion) can be understood by examining its electron configuration and applying the Valence Shell Electron Pair Repulsion (VSEPR) theory.

Electron Configuration and VSEPR Theory:

  • Central Atom: Iodine (I)
  • Valence Electrons: Iodine has 7 valence electrons, and each chlorine (Cl) atom contributes 7 valence electrons. The negative charge on the ion adds one more electron, totaling 7 + (4 × 7) + 1 = 32 valence electrons.
  • Electron Pairs: These 32 electrons form 16 pairs. Four pairs are bonding pairs between iodine and chlorine atoms, and the remaining 12 pairs are lone pairs on the iodine atom.
  • Electron Geometry: According to VSEPR theory, the electron pairs around the central atom arrange themselves to minimize repulsion. With 16 electron pairs, the geometry is octahedral.
  • Molecular Geometry: The four bonding pairs occupy the equatorial positions of the octahedron, while the two lone pairs occupy the axial positions. This arrangement results in a square planar molecular geometry for ICl₄⁻.

Summary:

The ICl₄⁻ ion has a square planar structure due to the arrangement of bonding and lone electron pairs around the central iodine atom.

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