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The substance undergoes first order decomposition. The decompostion follows two parallel first order reactions as :
$k_{1} = 1.26 \times 10^{- 4} \sec^{- 1}$ and $k_{2} = 3.8 \times 10^{- 5} \sec^{- 1} .$
The percentage distribution of B and C is :

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90%B and 10% C

76.83% B and 23.17% C

80% B and 20% C

answer is B.

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Detailed Solution

The ratio,

$\frac{[B]}{[C]} = \frac{k_{1}}{k_{2}} \Rightarrow % [B] = \frac{k_{1}}{k_{1} + k_{2}} \times 100$

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