The substances A, B and C can react to form C and D as shown below.
$2 A + 3 B + C \to 4 D + 2 E$
If molar masses of A, B, C and D are 40, 30, 20 and 15 respectively and 570 g of mixture of A, B, and C is reacted then calculate maximum mass of E which can be obtained (in gram).

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answer is 390.

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Detailed Solution

$\underset{2 a m o l e s}{2 A} + \underset{3 a m o l e s}{3 B} + \underset{a m o l e s}{C} \to 4 D + 2 E$
For obtaining maximum mass of E there should be no reactant after reaction
$∴ 2 a \times 40 + 3 a \times 30 + a \times 20 = 570$
$190 a = 570$
$a = 3$
$∴ n_{A} = 6 m o l e n_{B} = 9 m o l e n_{C} = 3 m o l e \Rightarrow 4 \times 3 m o l e o f D a n d 2 \times 3 m o l e s o f E ∴ M a s s o f D = 12 \times 15 = 180 g M a s s o f A + B + C = m a s s o f (D) + (E) (m a s s c o n v e r v a t i o n) 570 = 180 + m a s s o f E m a s s o f E = 390 g$