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The successive ionization energies in kJ/mol of an element P are 740, 1500, 7000, 10500, 13600, 18000 and 21700. which ion is the most likely to be formed when P reacts with chloride?

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P⁺

P^2–

P²⁺

P³⁺

answer is C.

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Detailed Solution

The largest relative increase in IE is in going from 1500 to 7000 kJ/mole. This represents the loss of a third electron, so P is likely to lose only 2 electrons making the ion P²⁺.

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