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The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with ZnSO₄.7H₂O. The atomic weight of M is

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11.3

24.3

36.3

40.3

answer is C.

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Detailed Solution

Consider the molecular weight of the metal be M

As it is isomorphous with ZnSO₄.7H₂O, the formula would be MSO₄.7H₂O

Percentage of M in the compound =

$M \times \frac{100}{M} + weight of {SO}_{4} + 7 \times weight of H_{2} O = \frac{M \times 100}{M + 96 + 126} = 9.87$

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