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Q.


The sum of a two-digit number and the number formed by reversing the digits of the number is 88. One of the digits of the number is three times the other digit. The number is ____.

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Detailed Solution

The sum of a two-digit number and the number formed by reversing the digits of the number is 88. One of the digits of the number is three times the other digit. The number is 62.
Let the ones place digit of the number be ‘x’.
Then, according to the condition given, the tens place digit will be = 3x
The two-digit number = 10(3x) + x = 31x
The reversed number = 10(x) + 3x = 13x
So,
⇒original number + reversed number = 88 ⇒31x + 13x = 88 ⇒44x = 88 ⇒x=2 The original number is 62.
Therefore, the required integer is 62.
 
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