The sum of a two-digit number is eight. The number obtained by reversing the digits exceeds the number by 18. Then the given no. is_________.

Let, the digit at units’ place = x and digit at ten’s place = y  

Now as per question, 

 x + y = 8, and,  

10x + y = 18 + (10y + x)  

$\Rightarrow$ x = 8 - y

$\Rightarrow$10 (8 - y) + y =18 + (10y + 8-y) {Substituting the value of x}

$\Rightarrow$80 - 10y + y =18 + 10y + 8 - y

$\Rightarrow$-9y -9y = 18 + 8 - 80

$\Rightarrow$-18y = -54

$\Rightarrow$y = -54/-18

$\Rightarrow$y = 3

$\Rightarrow$x = 8 - 3

$\Rightarrow$x = 5

Therefore, the number is 35.