Q.

The sum of absolute maximum and absolute minimum values of the function f(x)=2x2+3x2+sinxcosx  in the interval [0, 1] is :

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a

3+12(1+2cos(1))sin(1)

b

2+sin12cos12

c

3+sin(1)cos2(1/2)2

d

5+12(sin(1)+sin(2))

answer is B.

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Detailed Solution

f(x)=2x2+3x2+sinxcosxf(x)=|(2x1)(x+2)|+sinxcosx
f(x)=4x+3+cos2x4,12<x<1(4x+3)+cos2x4,0x<12
For 0x<12f(x)<0
For 12<x1f(x)>0
f (x) local minima at x=12 and 
local maxima at x = 1 
f12+f(1)=3+12(1+2cos1)sin1

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