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Q.

The sum of all the numbers formed by taking all the digits from 2, 3, 4, 5 is

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a

6660000

b

93325

c

93324

d

10368000

answer is C.

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Detailed Solution

Sum of numbers formed by taking all the digits from {2, 3, 4, 5}

     =(n-1)! (sum of digits) (1111)

     =3! (2+3+4+5) (1111)

     =6(14) (1111)

     =93,324                  option (3) is correct.

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