Q.

The sum of all the numbers greater than 10000 formed by using digits 0, 2, 4, 6, 8, no digit being repeated in any number, is equal to

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a

5209960

b

5199980

c

5299960

d

5199960

answer is A.

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Detailed Solution

Sum of all numbers greater than 10,000 using 0, 2, 4, 6, 8

sum of 5 digit numbers - sum of 5 digit numbers begin with 0

sum of numbers=(5-1)!(2+4+6+8)(11, 111)-(4-1)!(2+4+6+8)(1, 111)           =4!(20) (11, 111) - 3! (20) (1111)             =  20 (24(11, 111)-6(1111))                  = 20(266,664-6666)                      =20(259998)                      =5199960 

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