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Q.

The sum of an infinite GP with common ratio r(r<1) is 4 . The sum of the infinite GP obtained by squaring the terms  of this GP is 163 Then the first term and common ratio of the given GP is  

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a

−2,12

b

−2,13

c

2,12

d

3,−12

answer is C.

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Detailed Solution

a1−r=4                        ……………………(1)

a21−r2=163                  ………………………(2)

Solving,   a=2, r=12.

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