The sum of coordination number and oxidation number of the metal M in the complex $[M {(e n)}_{2} (C_{2} O_{4})] C l$ (where en is ethylenediamine) is

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answer is D.

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Detailed Solution

$[M {(e n)}_{2} (C_{2} O_{4})] C l :$
Oxidation number of metal = + 3
Coordination number of metal = 6
$∴$ Sum of oxidation number and coordination number = 3 + 6 = 9

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