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The sum of coordination number and oxidation number of the metal M in the complex $[M (e n)_{2} (C_{2} O_{4})] Cl$ (where en is ethylenediamine) is

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answer is D.

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Detailed Solution

$[M (en)_{2} (C_{2} O_{4})] Cl :$

en…neutral, bidentate

oxolato…bivalent,negative,bidentate

Oxidation number of metal = +3

Coordination number of metal = 6

$∴$ Sum of oxidation number and coordination number = 3 + 6 = 9

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