The sum of coordination number and oxidation numbers of x in the compound $\left[\mathrm{x}{\left({\mathrm{NH}}_3\right)}_5\left({\mathrm{SO}}_4\right)\right]\mathrm{Cl}$ will be equal to

In $\left[\mathrm{x}{\left({\mathrm{NH}}_3\right)}_5\left({\mathrm{SO}}_4\right)\right]\mathrm{Cl}$, both ammonia (NH₃​) and sulphate (SO₄​) are mono dentate ligands. Therefore, the coordination number of x is 6.

Oxidation state of x is:

$$\begin{gathered} \mathrm{oxidation} \mathrm{state} \mathrm{of} \mathrm{x}+\left(-2\right)+\left(-1\right)=0 \\ \mathrm{oxidation} \mathrm{state} \mathrm{of} \mathrm{x}=+3 \end{gathered}$$

Sum is 9 (6+3).