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Q.

The sum of first 10 natural numbers is

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a

100

b

10

c

55

d

45

answer is B.

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Detailed Solution

The sum of first

' n'

natural numbers is

\frac{n (n + 1)}{2}

The sum of first 10 natural numbers is $\frac{10 (10 + 1)}{2}$

$= \frac{10 \times 11}{2}$

$= 55$

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