The sum of orbital  angular Momentum, spherical nodes and angular nodes in ${\psi }_{3,2,1}$ is           

${\Psi }_{3,2,1}$ means n=3, $l=2$ and m = 1

Angular momentum =$\sqrt{l(l+1).}\frac{h}{2\pi }$

  =$\sqrt{2(2+1).}\frac{h}{2\pi }$ = $\frac{\sqrt{6.}h}{2\pi }$

  Spherical nodes = $n-l-1$

   = 3-2-1 =0

Angular nodes $l=2$

 $\therefore$Sum of the above factors = $\frac{\sqrt{6.}h}{2\pi }+0+2$ 

= $\frac{\sqrt{6.}h+4\pi }{2\pi }$