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Q.

The sum of positive integral divisors of 600 which are multiples of 10 is

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a

1680

b

840

c

3360

d

420

answer is C.

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Detailed Solution

$600 = 2^{3} \times 5^{2} \times 3 Sum of divisors which are multiples of 10 = (2 + 2^{2} + 2^{3}) (5 + 5^{2}) (1 + 3) = 14 (30) 4 = 1680$

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