The sum of positive number and it’s Reciprocal is thrice the difference of the number and it’s reciprocal. The number is

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$\frac{1}{\sqrt{2}}$

$\frac{1}{\sqrt{3}}$

$\sqrt{3}$

$\sqrt{2}$

answer is A.

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Detailed Solution

$\begin{array}{l} n + \frac{1}{n} = 3 (n - \frac{1}{n}) \\ n + \frac{1}{n} = 3 n - \frac{3}{n} \\ m u l t i p l y n o n b o t h s i d e s \\ n^{2} + 1 = 3 n^{2} - 3 \\ 4^{2} = 2 n^{2} \\ n^{2} = 2 \\ n = \sqrt{2} \end{array}$

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