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The sum of series 1, 3, 5, 7, 9,…… up to n terms is

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n^{2}

n^{3}

answer is C.

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Detailed Solution

Let a and d be the first term and common difference of the A.P.
a = 1 and d = 3-1 = 2

S_{n} = \frac{n}{2} [2 a + (n - 1) d]

\Rightarrow S_{n} = \frac{n}{2} [2 \times 1 + (n - 1) 2] = \frac{n}{2} \times (2 + 2 n - 2) = n^{2}

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