The sum of sum of divisor of 24 and product of divisor 24 is 

$\sigma \left(24\right)=\left(\frac{2^{3+1}-1}{2-1}\right)\left(\frac{3^{1+1}-1}{3-1}\right)$

$=\frac{15}{1}\times \frac{8}{2}$

$=60$

Product of divisors of  $24={24}^{\frac{1}{2}\left(3+1\right)\left(1+1\right)}={24}^{\frac{1}{2}\left(4\right)\left(2\right)}={24}^{\frac{8}{2}}={24}^4=331776$

Sum $=60+331776=331836$