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Q.


The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.

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a

18

b

23

c

21

d

15 

answer is A.

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Detailed Solution

It is given the sum of the digits of a two-digit number is 9.
The general form of linear equations in two variables is: ax + by + c = 0
Assume the ones place of the digit to be ‘x’ and tens place to be ‘y’.
Original number = 10y+x
Reversed number = 10x+y
Then according to the question, f
x+y=9 ………. equation (1)
And,
9×(10y+x)=2×(10x+y) ………equation (2)
Simplifying the two equations we get,
x+y=9 88y=11x
We get,
x=8y  Substituting the value of x in the other equation,
x+y=9 8y+y=9 9y=9 y=1 So,
x=8 The original number will be = 10×1+8=18
Hence option (1) is correct.
 
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The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.