Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The sum of the first 10 terms of an AP is -150 and the sum of its next 10 terms is -550. What is the AP?


see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

4, -1, -7, -8,.....

b

1, -1, -4, -7,..... 

c

3, -1, -5, -9,.....

d

2, -3, -6, -9,.....

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Given: S 10 =150  and the sum of its next 10 terms is −550.
Let a be the first term and d be the common difference of the A.P.
Formula for sum of n terms of an A.P. formula:
S n = n 2 [2a+(n1)d] Applying sum of nth term of an A.P. formula in first given condition: S 10 =150 10 2 (2a+9d)=150 5(2a+9d)=150 2a+9d=30(1)
S 20 = sum of first 20 terms.
S 20 = sum of first 10 terms + sum of next 10 terms.
=150+(550) =700 Applying sum of nth term of an A.P. formula in second given condition: S 20 =700 20 2 (2a+19d)=700 10(2a+19d)=700 2a+19d=70(2)
Subtract equation (1) from equation (2):
2a+19d2a9d=70(30) 10d=40 d= 40 10 d=4 Substitute the value of d in equation (1):
2a+9×(4)=30 2a=30+36 2a=6 a=3 Therefore, the required A.P. is 3, -1, -5, -9,.....
Hence, option (3) is correct.
 
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring