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Q.

The sum of the first 40 positive integers divisible by 6 is ____.


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Detailed Solution

The sum of the first 40 positive integers divisible by 6 is 4920.
We have been given first 40 positive integers.
As we know that first 40 positive integers divisible by 6 are 6, 12, 18, 24, … to 40 terms.
Formula used for sum of first term of A.P.:
S n = n 2 2a+ n−1 ×d
 Put a=6,d=6,n=40 .
S 40 = 40 2 2×6+ 40−1 ×6
S 40 =20 12+39×6 ⇒ S 40 =20× 12+234 ⇒ S 40 =20×246 ⇒ S 40 =4920 Therefore, the sum of the first 40 positive integers divisible by 6 is 4920.
 
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