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The sum of the minimum and maximum distances of the point (4,-3) to the circle $x^{2} + y^{2} + 4 x - 10 y - 7 = 0$ is

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answer is A.

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Detailed Solution

$p (4, - 3), c = (- 2, 5), r = 6$

$c p - r + c p + r$

$= 2 c p = 2 \sqrt{36 + 64} = 20$

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