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Q.

The sum of the roots of the equation x2+px+q=0  is equal to the sum of their squares, then

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a

p2+p=2q

b

q2+q=2p

c

p2-q2=0

d

p2+q2=2q

answer is C.

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Detailed Solution

x2+px+q=0

as per sum

α+β=α2+β2

α+β=(α+β)2-2αβ

-p=(-p)2-2q

p2+p=2q

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