The sum of the roots of $\sqrt{2}{x}^2-4x+6=0$ is

Given quadratic equation is $\sqrt{2}{x}^2-4x+6=0$

Sum of its roots$=\frac{-coefficientofx}{coefficientof{x}^2}$

$=\left(\frac{-b}{a}\right)$

$=\frac{-(-4)}{\sqrt{2}}$

$=\frac{4}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}$

$=\frac{4\sqrt{2}}{2}$

$=2\sqrt{2}$