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Q.

The sum of the series 5 +55 +555 +...to n terms is

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a

18010n+1

b

58110n+19n10

c

58110n18n1

d

58110n+1+9n+10

answer is B.

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Detailed Solution

5 + 55 + 555 +...to n terms

=5 {1+ 1 1 + 1 1 1 +...to n terms} 

=59{9+99+999+ to n terms }

[multiply numerator and denominator by 9]

=59{(101)+(1001)+(10001)+ to n terms }=59{10+100+1000++n terms (1+1++n terms )}=591010n1101n=58110n+1109n

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