The sum of those integers between 1 and 500 which are multiples of 2 as well as 5 is

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12500

12250

12570

13520

answer is B.

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Detailed Solution

Given the AP series is integers between 1 and 500 which are multiples of 2 as well as 5.
So, the series of numbers will be 10,20,30.....490. Putting, a = 10, d = 10 and

a n

= 490 in the above expression.

490 = 10 + n − 1 10 n − 1 10 = 480 n − 1 = 48 n = 49

Now, putting n = 49, the sum is,

S n = n 2 2 a + n − 1 d

S 49 = 492 210 + 49 − 1 10 S 49 = 492 20 + 480 S 49 = 49 × 250 S 49 = 12250

So, the sum is 12250.
Therefore, the correct option is 2.

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