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Q.

The sum of three consecutive integers is 45. Find the integers.


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a

14,15,16

b

12,13,14

c

15,16,17

d

16,17,18 

answer is A.

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Detailed Solution

Concept- In this question, first of all assume three consecutive integers as x, (x + 1)  and (x + 2) . Now, add them and equate to forty five and find the value of x from the equation, and from x, find the 3 consecutive integers.
Value of the first integer = x Let this equation as equation (1)
Value of the second integer = x + 1
Let this equation as equation (2)
Value of the third integer = x + 2
Let this equation as equation (3)
Given that the sum of three subsequent integers is 45.
So, we get,
(First Integer) + (second Integer) + (Third Integer) = 45 By substituting the value of the first, second and third integers from equation (1) , (2) and (3)
3x + 3 = 45 3x = 45 – 3 3x = 42 x=423 x = 14 So, we get  the first integer = x = 14
Value of the second integer = x + 1 = 15
Value of the third integer = x + 2 = 16
Hence, the correct option is 1) 14, 15, 16
 
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