The sum of three consecutive multiples of 6 is 72. Find the numbers.

Let $x$ be a multiple of 6.

The next multiples will be $x+6$ and $x+12$

Given, sum of multiples is 72

So, $x+(x+6)+(x+12)=72$

                           $$\begin{gathered} 3x+18=72 \\ 3x=72-18 \\ 3x=54 \\ x=\frac{54}{3} \\ x=18 \end{gathered}$$

The next multiples will be 18+6=24 and 18+12=30

So, the multiples are 18, 24 and 30